The atomic radius of Ag is closed to : - DASH

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The atomic radius of Ag is closed to :

Au

Cu

Hg

Ni

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Step-by-Step Explanation 1. Introduction The question is about comparing the atomic radii of silver (Ag) with other metals in the periodic table. Specifically, we want to know to which metal Ag’s atomic radius is closest. The correct answer is gold (Au). 2. Role of Lanthanide Contraction As we move from the 3d to 4d and then to the 5d series in the periodic table, we normally expect the size of the atoms to increase because of the additional electron shells. However, the phenomenon known as lanthanide contraction significantly reduces the expected increase in radius in the 5d series. This effect occurs due to the poor shielding of the nuclear charge by the 4f electrons in the lanthanide elements. As a result, the 5d elements (including gold, Au) do not become as large as might be expected. 3. Comparison of Ag and Au Radii Silver (Ag) belongs to the 4d series and gold (Au) belongs to the 5d series. Because of the strong effect of lanthanide contraction on the 5d elements, gold’s radius is much smaller than expected, making the atomic radius of Au very close to that of Ag. Hence, even though Au is in the 5d series, its radius is not significantly larger than Ag. 4. Conclusion Therefore, the atomic radius of Ag is most similar to that of Au (option 1), which is attributed to the lanthanide contraction that limits the increase in atomic size in the 5d series.

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