Let xk + yk = ak, (a, k > 0 ) and ${{dy} \over {dx}} + {\left( {{y \over x}} \right)^{{1 \over 3}}} = 0$, then k is:

Question

Let x^k + y^k = a^k, (a, k > 0 ) and ${{dy} \over {dx}} + {\left( {{y \over x}} \right)^{{1 \over 3}}} = 0$, then k is:

${1 \over 3}$

${2 \over 3}$

${4 \over 3}$

${3 \over 2}$

Please login to view the detailed solution steps...