If g(x) = x2 + x - 1 and (goƒ) (x) = 4x2 - 10x + 5, then ƒ$\left( {{5 \over 4}} \right)$ is equal to:

Question

If g(x) = x² + x - 1 and
(goƒ) (x) = 4x² - 10x + 5, then ƒ$\left( {{5 \over 4}} \right)$ is equal to:

${1 \over 2}$

${3 \over 2}$

-${1 \over 2}$

-${3 \over 2}$

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