A particle is moving with speed v = b$\sqrt x $ along positive x-axis. Calculate the speed of the particle at
time t = $\tau $(assume that the particle is at origin t = 0)
${{{b^2}\tau } \over {\sqrt 2 }}$
${{b^2}\tau }$
${{{b^2}\tau } \over 2}$
${{{b^2}\tau } \over 4}$
Solution
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