Given CO3+ + e– $ \to $ CO2+ ; Eo = + 1.81 V Pb4+ + 2e– $ \to $ Pb2+ ; Eo = + 1.67 V Ce4+ + e– $ \to $ Ce3+ ; Eo = + 1.61 V Bi3+ + 3e– $ \to $ Bi ; Eo = + 0.20 V Oxidizing power of the species will increase in the order :

Question

Given

CO³⁺ + e^– $ \to $ CO₂⁺ ; E^o = + 1.81 V

Pb⁴⁺ + 2e^– $ \to $ Pb₂⁺ ; E^o = + 1.67 V

Ce⁴⁺ + e^– $ \to $ Ce³⁺ ; E^o = + 1.61 V

Bi³⁺ + 3e^– $ \to $ Bi ; E^o = + 0.20 V

Oxidizing power of the species will increase in the order :

Co³⁺ < Ce⁴⁺ < Bi³⁺ < Pb⁴⁺

Co³⁺ < Pb⁴⁺ < Ce⁴⁺ < Bi³⁺

Ce⁴⁺ < Pb⁴⁺ < Bi³⁺ < Co³⁺

Bi³⁺ < Ce⁴⁺ < Pb⁴⁺ < Co³⁺

Solution

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