For x $ \in $ (0, 3/2), let f(x) = $\sqrt x $ , g(x) = tan x and h(x) = ${{1 - {x^2}} \over {1 + {x^2}}}$. If $\phi $ (x) = ((hof)og)(x), then $\phi \left( {{\pi \over 3}} \right)$
is equal to :
$\tan {{7\pi } \over {12}}$
$\tan {{11\pi } \over {12}}$
$\tan {\pi \over {12}}$
$\tan {{5\pi } \over {12}}$
Solution
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