If m is the minimum value of k for which the function f(x) = x$\sqrt {kx - {x^2}} $ is increasing in the interval [0,3]
and M is the maximum value of f in [0, 3] when k = m, then the ordered pair (m, M) is equal to :
$\left( {5,3\sqrt 6 } \right)$
$\left( {4,3\sqrt 3 } \right)$
$\left( {4,3\sqrt 2 } \right)$
$\left( {3,3\sqrt 3 } \right)$
Solution
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