Consider the differential equation, ${y^2}dx + \left( {x - {1 \over y}} \right)dy = 0$, If value of y is 1 when x = 1, then the value of x
for which y = 2, is :
${3 \over 2} - {1 \over {\sqrt e }}$
${1 \over 2} + {1 \over {\sqrt e }}$
${5 \over 2} + {1 \over {\sqrt e }}$
${3 \over 2} - \sqrt e $
Solution
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