If the area (in sq. units) of the region {(x, y) : y2
$ \le $ 4x, x + y $ \le $ 1, x $ \ge $ 0, y $ \ge $ 0} is a $\sqrt 2 $ + b, then a – b is equal
to :
${8 \over 3}$
$ - {2 \over 3}$
6
${{10} \over 3}$
Solution
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