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Question

The truth table for the circuit given in the fig. is:

$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 1 \cr 1 & 0 & 1 \cr 1 & 1 & 1 \cr } } \right|$$
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 0 \cr 1 & 0 & 0 \cr 1 & 1 & 0 \cr } } \right|$$
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 1 \cr 1 & 0 & 0 \cr 1 & 1 & 0 \cr } } \right|$$
$$\left| {\matrix{ A & B & Y \cr 0 & 0 & 0 \cr 0 & 1 & 0 \cr 1 & 0 & 1 \cr 1 & 1 & 1 \cr } } \right|$$

Solution

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