The minimum amount of O2(g) consumed per gram of reactant is for the reaction : (Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)

Question

The minimum amount of O₂(g) consumed per gram of reactant is for the reaction :
(Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)

4Fe(s) + 3O₂(g) $ \to $ 2Fe₂O₃(s)

P₄(s) + 5O₂(g) $ \to $ P₄O₁₀(s)

C₃H₈(g) + 5O₂(g) $ \to $ 3CO₂(g) + 4H₂O(l)

2Mg(s) + O₂(g) $ \to $ 2MgO(s)

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