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Question
Let $\lambda $ be a real number for which the system of linear equations x + y + z = 6, 4x + $\lambda $y – $\lambda $z = $\lambda $ – 2, 3x + 2y – 4z = – 5 has infinitely many solutions. Then $\lambda $ is a root of the quadratic equation:
$\lambda $2 + $\lambda $ - 6 = 0
$\lambda $2 - $\lambda $ - 6 = 0
$\lambda $2 - 3$\lambda $ - 4 = 0
$\lambda $2 + 3$\lambda $ - 4 = 0

Solution

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