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Question
The area (in sq.units) of the region bounded by the curves y = 2x and y = |x + 1|, in the first quadrant is :
${1 \over 2}$
${3 \over 2}$
${3 \over 2} - {1 \over {\log _e^2}}$
$\log _e^2 + {3 \over 2}$

Solution

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