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Question
A square loop is carrying a steady current I and the magnitude of its magnetic dipole moment is m. if this square loop is changed to a circular loop and it carries the same current, the magnitude of the magnetic dipole moment of circular loop will be:
${m \over \pi }$
${{3m} \over \pi }$
${{2m} \over \pi }$
${{4m} \over \pi }$

Solution

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