A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by :

Question

$2\pi \sqrt {{L \over {\sqrt {{g^2} - {{{q^2}{E^2}} \over {{m^2}}}} }}} $

$2\pi \sqrt {{L \over {\left( {g + {{qE} \over m}} \right)}}} $

$2\pi \sqrt {{L \over {\sqrt {{g^2} + {{{q^2}{E^2}} \over {{m^2}}}} }}} $

$2\pi \sqrt {{L \over {\left( {g - {{qE} \over m}} \right)}}} $

Solution

Please login to view the detailed solution steps...

Go to DASH