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Question
If $\mathop {\lim }\limits_{x \to 1} {{{x^4} - 1} \over {x - 1}} = \mathop {\lim }\limits_{x \to k} {{{x^3} - {k^3}} \over {{x^2} - {k^2}}}$, then k is :
${3 \over 2}$
${8 \over 3}$
${4 \over 3}$
${3 \over 8}$

Solution

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