The electric field of a plane electromagnetic wave is given by $\overrightarrow E = {E_0}\widehat i\cos (kz)cos(\omega t)$ The corresponding magnetic field $\overrightarrow B $ is then given by

Question

The electric field of a plane electromagnetic wave is given by
$\overrightarrow E = {E_0}\widehat i\cos (kz)cos(\omega t)$
The corresponding magnetic field $\overrightarrow B $ is then given by

$\overrightarrow B = {{{E_0}} \over C}\widehat j\sin (kz)\sin (\omega t)$

$\overrightarrow B = {{{E_0}} \over C}\widehat j\sin (kz)\cos (\omega t)$

$\overrightarrow B = {{{E_0}} \over C}\widehat j\cos (kz)\sin (\omega t)$

$\overrightarrow B = {{{E_0}} \over C}\widehat k\sin (kz)\cos (\omega t)$

Solution

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