In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line. One may conclude that :

Question

$R(T) = {R_0}{e^{ - {T^2}/T_0^2}}$

$R(T) = {{{R_0}} \over {{T^2}}}$

$R(T) = {R_0}{e^{ {T^2}/T_0^2}}$

$R(T) = {R_0}{e^{ - T_0^2/{T^2}}}$

Solution

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