The vertices B and C of a $\Delta $ABC lie on the line, ${{x + 2} \over 3} = {{y - 1} \over 0} = {z \over 4}$ such that BC = 5 units. Then the area (in sq. units) of this triangle, given that the point A(1, –1, 2), is :

Question

The vertices B and C of a $\Delta $ABC lie on the line,

${{x + 2} \over 3} = {{y - 1} \over 0} = {z \over 4}$ such that BC = 5 units.

Then the area (in sq. units) of this triangle, given that the point A(1, –1, 2), is :

$5\sqrt {17} $