The position of a particle as a function of time t, is given byx(t) = at + bt2 – ct3 where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be :

Question

The position of a particle as a function of time t, is given by
x(t) = at + bt² – ct³
where a, b and c are constants. When the particle attains zero acceleration, then its velocity will be :

$a + {{{b^2}} \over {c}}$

$a + {{{b^2}} \over {4c}}$

$a + {{{b^2}} \over {3c}}$

$a + {{{b^2}} \over {2c}}$

Solution

Please login to view the detailed solution steps...

Go to DASH