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Question
The standard Gibbs energy for the given cell reaction in kJ mol–1 at 298 K is :

Zn(s) + Cu2+ (aq) $ \to $ Zn2+ (aq) + Cu (s),

E° = 2 V at 298 K

(Faraday's constant, F = 96000 C mol–1)
384
–192
–384
192

Solution

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