A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of $\theta $, where $\theta $ is the angle by which it has rotated, is given as k$\theta $2. If its moment of inertia is I then the angular acceleration of the disc is :

Question

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of $\theta $, where $\theta $ is the angle by which it has rotated, is given as k$\theta $². If its moment of inertia is I then the angular acceleration of the disc is :

${k \over {4I}}\theta $

${k \over {I}}\theta $

${k \over {2I}}\theta $

${2k \over {I}}\theta $

Solution

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