If the system of linear equations x – 2y + kz = 1 2x + y + z = 2 3x – y – kz = 3 has a solution (x,y,z), z $ \ne $ 0, then (x,y) lies on the straight line whose equation is :

Question

If the system of linear equations

x – 2y + kz = 1
2x + y + z = 2
3x – y – kz = 3

has a solution (x,y,z), z $ \ne $ 0, then (x,y) lies on the straight line whose equation is :

4x – 3y – 4 = 0

3x – 4y – 1 = 0

4x – 3y – 1 = 0

3x – 4y – 4 = 0

Solution

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