Given that ${E^\Theta }_{{O_2}/{H_2}O} = 1.23\,V$ ; ${E^\Theta }_{{S_2}O_8^{2 - }/SO_4^{2 - }} = 2.05\,V$ ${E^\Theta }_{B{r_2}/B{r^ - }} = 1.09\,V$ ${E^\Theta }_{A{u^{3 + }}/Au} = 1.4\,V$ The strongest oxidizing agent is :

Question

Given that ${E^\Theta }_{{O_2}/{H_2}O} = 1.23\,V$ ;

${E^\Theta }_{{S_2}O_8^{2 - }/SO_4^{2 - }} = 2.05\,V$

${E^\Theta }_{B{r_2}/B{r^ - }} = 1.09\,V$

${E^\Theta }_{A{u^{3 + }}/Au} = 1.4\,V$

The strongest oxidizing agent is :

O₂

Au³⁺

Br₂

${S_2}O_8^{2 - }$

Solution

Please login to view the detailed solution steps...

Go to DASH