If $f(x) = {\log _e}\left( {{{1 - x} \over {1 + x}}} \right)$, $\left| x \right| < 1$ then $f\left( {{{2x} \over {1 + {x^2}}}} \right)$ is equal to - DASH

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Question

If $f(x) = {\log _e}\left( {{{1 - x} \over {1 + x}}} \right)$, $\left| x \right| < 1$ then $f\left( {{{2x} \over {1 + {x^2}}}} \right)$ is equal to

2f(x²)

2f(x)

(f(x))²

-2f(x)

Solution

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