If $2y = {\left( {{{\cot }^{ - 1}}\left( {{{\sqrt 3 \cos x + \sin x} \over {\cos x - \sqrt 3 \sin x}}} \right)} \right)^2}$, x $ \in $ $\left( {0,{\pi \over 2}} \right)$ then $dy \over dx$ is equal to:

Question

If $2y = {\left( {{{\cot }^{ - 1}}\left( {{{\sqrt 3 \cos x + \sin x} \over {\cos x - \sqrt 3 \sin x}}} \right)} \right)^2}$,

x $ \in $ $\left( {0,{\pi \over 2}} \right)$ then $dy \over dx$ is equal to:

$2x - {\pi \over 3}$

${\pi \over 6} - x$

${\pi \over 3} - x$

$x - {\pi \over 6}$

Solution

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