Four identical particles of mass M are located at the corners of a square of side 'a'. What should be their speed if each of them revolves under the influence of other's gravitational field in a circular orbit circumscribing the square?

Question

$1.21\sqrt {{{GM} \over a}} $

$1.16\sqrt {{{GM} \over a}} $

$1.41\sqrt {{{GM} \over a}} $

$1.35\sqrt {{{GM} \over a}} $

Solution

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