Two particles move at right angle to each other. Their de-Broglie wavelengths are $\lambda _1$ and $\lambda _2$ respectively. The particles suffer perfectly inelastic collision. The de-Broglie wavelength $\lambda _2$ of the final particle, is given by :

Question

$\lambda = {{{\lambda _1} + {\lambda _2}} \over 2}$

${1 \over {{\lambda ^2}}} = {1 \over {\lambda _1^2}} + {1 \over {\lambda _2^2}}$

$\lambda = \sqrt {{\lambda _1}{\lambda _2}} $

${2 \over \lambda } = {1 \over {{\lambda _1}}} + {1 \over {{\lambda _2}}}$

Solution

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