If a curve passes through the point (1, –2) and has slope of the tangent at any point (x, y) on it as ${{{x^2} - 2y} \over x}$, then the curve also passes through the point :
(–1, 2)
$\left( { - \sqrt 2 ,1} \right)$
$\left( { \sqrt 3 ,0} \right)$
(3, 0)
Solution
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