Two particles A, B are moving on two concentric circles of radii R1 and R2 with equal angular speed $\omega $. At t = 0, their positions and direction of motion are shown in the figure. : The relative velocity ${\overrightarrow V _A} - {\overrightarrow V _B}$ at t = ${\pi \over {2\omega }}$ is given by :

Question

Two particles A, B are moving on two concentric circles of radii R₁ and R₂ with equal angular speed $\omega $. At t = 0, their positions and direction of motion are shown in the figure. :

The relative velocity ${\overrightarrow V _A} - {\overrightarrow V _B}$ at t = ${\pi \over {2\omega }}$ is given by :

$ - \omega \left( {{R_1} + {R_2}} \right)\,\widehat i$

$\omega \left( {{R_2} - {R_1}} \right)\,\widehat i$

$\omega \left( {{R_1} + {R_2}} \right)\,\widehat i$

$\omega \left( {{R_1} - {R_1}} \right)\,\widehat i$

Solution

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