The integral $\int \, $cos(loge x) dx is equal to : (where C is a constant of integration)

Question

The integral $\int \, $cos(log_e x) dx is equal to : (where C is a constant of integration)

${x \over 2}$[sin(log_e x) $-$ cos(log_e x)] + C

x[cos(log_e x) + sin(log_e x)] + C

${x \over 2}$[cos(log_e x) + sin(log_e x)] + C

x[cos(log_e x) $-$ sin(log_e x)] + C

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