If $\lambda $ be the ratio of the roots of the quadratic equation in x, 3m2x2 + m(m – 4)x + 2 = 0, then the least value of m for which $\lambda + {1 \over \lambda } = 1,$ is

Question

If $\lambda $ be the ratio of the roots of the quadratic equation in x, 3m²x² + m(m – 4)x + 2 = 0, then the least value of m for which $\lambda + {1 \over \lambda } = 1,$ is

$ - 2 + \sqrt 2 $

4$-$3$\sqrt 2 $

2 $-$ $\sqrt 3 $

4 $-$ 2$\sqrt 3 $

Solution

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