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Question
Given the equilibrium constant:

KC of the reaction :

Cu(s) + 2Ag+ (aq) $ \to $ Cu2+ (aq) + 2Ag(s) is

10 $ \times $ 1015, calculate the E$_{cell}^0$ of this reaciton at 298 K

[2.303 ${{RT} \over F}$ at 298 K = 0.059V]
0.4736 mV
0.04736 V
0.4736 V
0.04736 mV

Solution

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