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Question
The solution of the differential equation,

${{dy} \over {dx}}$ = (x – y)2, when y(1) = 1, is :
$-$ loge $\left| {{{1 + x - y} \over {1 - x + y}}} \right|$ = x + y $-$ 2
loge $\left| {{{2 - x} \over {2 - y}}} \right|$ = x $-$ y
loge $\left| {{{2 - y} \over {2 - x}}} \right|$ = 2(y $-$ 1)
$-$ loge $\left| {{{1 - x + y} \over {1 + x - y}}} \right|$ = 2(x $-$ 1)

Solution

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