If $$\left| {\matrix{ {a - b - c} & {2a} & {2a} \cr {2b} & {b - c - a} & {2b} \cr {2c} & {2c} & {c - a - b} \cr } } \right|$$ = (a + b + c) (x + a + b + c)2, x $ \ne $ 0, then x is equal to :

Question

If $$\left| {\matrix{ {a - b - c} & {2a} & {2a} \cr {2b} & {b - c - a} & {2b} \cr {2c} & {2c} & {c - a - b} \cr } } \right|$$

= (a + b + c) (x + a + b + c)², x $ \ne $ 0,

then x is equal to :

–2(a + b + c)