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Question
If   $\int {{{x + 1} \over {\sqrt {2x - 1} }}} \,dx$ = f(x) $\sqrt {2x - 1} $ + C, where C is a constant of integration, then f(x) is equal to :
${2 \over 3}$ (x $-$ 4)
${1 \over 3}$ (x + 4)
${1 \over 3}$ (x + 1)
${2 \over 3}$ (x + 2)

Solution

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