The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians) :

Question

${\pi \over 8}$

${\pi \over 6}$

${\pi \over 4}$

${\pi \over 3}$

Solution

Please login to view the detailed solution steps...

Go to DASH