If one real root of the quadratic equation 81x2 + kx + 256 = 0 is cube of the other root, then a value of k is

Question

If one real root of the quadratic equation 81x² + kx + 256 = 0 is cube of the other root, then a value of k is

$-$ 81

$-$ 300

100

144

Please login to view the detailed solution steps...