A liquid of density $\rho $ is coming out of a hose pipe of radius a with horizontal speed $\upsilon $ and hits a mesh. 50% of
the liquid passes through the mesh unaffected. 25% looses all of its momentum and 25% comes back with the same speed. The resultant pressure on the mesh will be :
${3 \over 4}\rho {v^2}$
${1 \over 4}\rho {v^2}$
${1 \over 2}\rho {v^2}$
$\rho {v^2}$
Solution
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