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Question
Let  d $ \in $ R, and 

$$A = \left[ {\matrix{ { - 2} & {4 + d} & {\left( {\sin \theta } \right) - 2} \cr 1 & {\left( {\sin \theta } \right) + 2} & d \cr 5 & {\left( {2\sin \theta } \right) - d} & {\left( { - \sin \theta } \right) + 2 + 2d} \cr } } \right],$$

$\theta \in \left[ {0,2\pi } \right]$ If the minimum value of det(A) is 8, then a value of d is -
$-$ 7
$2\left( {\sqrt 2 + 2} \right)$
$-$ 5
$2\left( {\sqrt 2 + 1} \right)$

Solution

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