A heat source at T = 103 K is connected to another heat reservoir at T = 102 K by a copper slab which is 1 mthick. Given that the thermal conductivity of copper is 0.1 WK–1m–1, the energy flux through it in the steady state is -
200 Wm$-$2
65 Wm$-$2
120 Wm$-$2
90 Wm$-$2
Solution
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