If y = y(x) is the solution of the differential equation, x$dy \over dx$ + 2y = x2, satisfying y(1) = 1, then y($1\over2$) is equal to :

Question

If y = y(x) is the solution of the differential equation,

x$dy \over dx$ + 2y = x², satisfying y(1) = 1, then y($1\over2$) is equal to :

$ {{7} \over {64}}$

$ {{49} \over {16}}$

$ {{1} \over {4}}$

$ {{13} \over {16}}$

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