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Question
An unknown chlorohydrocarbon has 3.55% of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are :
(Atomic wt. of Cl = 35.5 u; Avogadro constant = 6.023 $ \times $ 1023 mol-1)
6.023 $ \times $ 1020
6.023 $ \times $ 109
6.023 $ \times $ 1021
6.023 $ \times $ 1023

Solution

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