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Question
Let p, q and r be real numbers (p $ \ne $ q, r $ \ne $ 0), such that the roots of the equation ${1 \over {x + p}} + {1 \over {x + q}} = {1 \over r}$ are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to :
${{{p^2} + {q^2}} \over 2}$
p2 + q2
2(p2 + q2)
p2 + q2 + r2

Solution

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