If $x = \sqrt {{2^{\cos e{c^{ - 1}}}}} $ and $y = \sqrt {{2^{se{c^{ - 1}}t}}} \,\,\left( {\left| t \right| \ge 1} \right),$ then ${{dy} \over {dx}}$ is equal to :

Question

${y \over x}$

${x \over y}$

$-$ ${y \over x}$

$-$ ${x \over y}$

Solution

Please login to view the detailed solution steps...

Go to DASH