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Question
If $f(x) = \int\limits_0^x {t\left( {\sin x - \sin t} \right)dt\,\,\,} $ then :
f'''(x) + f''(x) = sinx
f'''(x) + f''(x) $-$ f'(x) = cosx
f'''(x) + f'(x) = cosx $-$ 2x sinx
f'''(x) $-$ f''(x) = cosx $-$ 2x sinx

Solution

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