If the angle between the lines, ${x \over 2} = {y \over 2} = {z \over 1}$ and ${{5 - x} \over { - 2}} = {{7y - 14} \over p} = {{z - 3} \over 4}\,\,$ is ${\cos ^{ - 1}}\left( {{2 \over 3}} \right),$ then p is equal to :

Question

If the angle between the lines, ${x \over 2} = {y \over 2} = {z \over 1}$

and ${{5 - x} \over { - 2}} = {{7y - 14} \over p} = {{z - 3} \over 4}\,\,$ is ${\cos ^{ - 1}}\left( {{2 \over 3}} \right),$ then p is equal to :

${7 \over 2}$

${2 \over 7}$

$-$ ${7 \over 4}$

$-$ ${4 \over 7}$

Solution

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