Two sets A and B are as under : A = {($a$, b) $ \in $ R $ \times $ R : |$a$ - 5| < 1 and |b - 5| < 1}; B = {($a$, b) $ \in $ R $ \times $ R : 4($a$ - 6)2 + 9(b - 5)2 $ \le $ 36 }; Then

Question

Two sets A and B are as under :

A = {($a$, b) $ \in $ R $ \times $ R : |$a$ - 5| < 1 and |b - 5| < 1};

B = {($a$, b) $ \in $ R $ \times $ R : 4($a$ - 6)² + 9(b - 5)² $ \le $ 36 };

Then

neither A $ \subset $ B nor B $ \subset $ A

B $ \subset $ A

A $ \subset $ B

A $ \cap $ B = $\phi $ ( an empty set )

Solution

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