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Question
Given

(i)   2Fe2O3(s) $ \to $ 4Fe(s) + 3O2(g);

$\Delta $rGo = + 1487.0 kJ mol-1

(ii)   2CO(g) + O2(g) $ \to $ 2CO2(g);

$\Delta $rGo = $-$ 514.4 kJ mol-1

Free energy change, $\Delta $rGo for the reaction

2Fe2O3(s) + 6CO(g) $ \to $ 4Fe(s) + 6CO2(g) will be :
$-$ 112.4 kJ mol-1
$-$ 56.2 kJ mol-1
$-$ 168.2 kJ mol-1
$-$ 208.0 kJ mol-1

Solution

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