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Question
The value of integral $\int_{{\pi \over 4}}^{{{3\pi } \over 4}} {{x \over {1 + \sin x}}dx} $ is :
$\pi \sqrt 2 $
$\pi \left( {\sqrt 2 - 1} \right)$
${\pi \over 2}\left( {\sqrt 2 + 1} \right)$
$2\pi \left( {\sqrt 2 - 1} \right)$

Solution

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